DAA – Map Colouring Algorithm


Map Colouring Algorithm


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Map colouring problem states that given a graph G {V, E} where V and E are the set of vertices and edges of the graph, all vertices in V need to be coloured in such a way that no two adjacent vertices must have the same colour.

The real-world applications of this algorithm are – assigning mobile radio frequencies, making schedules, designing Sudoku, allocating registers etc.

Map Colouring Algorithm

With the map colouring algorithm, a graph G and the colours to be added to the graph are taken as an input and a coloured graph with no two adjacent vertices having the same colour is achieved.

Algorithm

  • Initiate all the vertices in the graph.

  • Select the node with the highest degree to colour it with any colour.

  • Choose the colour to be used on the graph with the help of the selection colour function so that no adjacent vertex is having the same colour.

  • Check if the colour can be added and if it does, add it to the solution set.

  • Repeat the process from step 2 until the output set is ready.

Examples


Map_Colouring_graph

Step 1

Find degrees of all the vertices −


A – 4
B – 2
C – 2
D – 3
E – 3

Step 2

Choose the vertex with the highest degree to colour first, i.e., A and choose a colour using selection colour function. Check if the colour can be added to the vertex and if yes, add it to the solution set.


highest_degree

Step 3

Select any vertex with the next highest degree from the remaining vertices and colour it using selection colour function.

D and E both have the next highest degree 3, so choose any one between them, say D.


d_highest_degree

D is adjacent to A, therefore it cannot be coloured in the same colour as A. Hence, choose a different colour using selection colour function.

Step 4

The next highest degree vertex is E, hence choose E.


E_highest_degree

E is adjacent to both A and D, therefore it cannot be coloured in the same colours as A and D. Choose a different colour using selection colour function.

Step 5

The next highest degree vertices are B and C. Thus, choose any one randomly.


B_and_C_highest_degree

B is adjacent to both A and E, thus not allowing to be coloured in the colours of A and E but it is not adjacent to D, so it can be coloured with D’s colour.

Step 6

The next and the last vertex remaining is C, which is adjacent to both A and D, not allowing it to be coloured using the colours of A and D. But it is not adjacent to E, so it can be coloured in E’s colour.


C_highest_degree

Example

Following is the complete implementation of Map Colouring Algorithm in various programming languages where a graph is coloured in such a way that no two adjacent vertices have same colour.


#include<stdio.h>
#include<stdbool.h>
#define V 4
bool graph[V][V] = {
   {0, 1, 1, 0},
   {1, 0, 1, 1},
   {1, 1, 0, 1},
   {0, 1, 1, 0},
};
bool isValid(int v,int color[], int c){   //check whether putting a color valid for v
   for (int i = 0; i < V; i++)
      if (graph[v][i] && c == color[i])
         return false;
   return true;
}
bool mColoring(int colors, int color[], int vertex){
   if (vertex == V) //when all vertices are considered
      return true;
   for (int col = 1; col <= colors; col++) {
      if (isValid(vertex,color, col)) { //check whether color col is valid or not
         color[vertex] = col;
         if (mColoring (colors, color, vertex+1) == true) //go for additional vertices
            return true;
         color[vertex] = 0;
      }
   }
   return false; //when no colors can be assigned
}
int main(){
   int colors = 3; // Number of colors
   int color[V]; //make color matrix for each vertex
   for (int i = 0; i < V; i++)
      color[i] = 0; //initially set to 0
   if (mColoring(colors, color, 0) == false) { //for vertex 0 check graph coloring
      printf("Solution does not exist.");
   }
   printf("Assigned Colors are: n");
   for (int i = 0; i < V; i++)
      printf("%d ", color[i]);
   return 0;
}

Output


Assigned Colors are:
1 2 3 1


#include<iostream>
using namespace std;
#define V 4
bool graph[V][V] = {
   {0, 1, 1, 0},
   {1, 0, 1, 1},
   {1, 1, 0, 1},
   {0, 1, 1, 0},
};
bool isValid(int v,int color[], int c){   //check whether putting a color valid for v
   for (int i = 0; i < V; i++)
      if (graph[v][i] && c == color[i])
         return false;
   return true;
}
bool mColoring(int colors, int color[], int vertex){
   if (vertex == V) //when all vertices are considered
      return true;
   for (int col = 1; col <= colors; col++) {
      if (isValid(vertex,color, col)) { //check whether color col is valid or not
         color[vertex] = col;
         if (mColoring (colors, color, vertex+1) == true) //go for additional vertices
            return true;
         color[vertex] = 0;
      }
   }
   return false; //when no colors can be assigned
}
int main(){
   int colors = 3; // Number of colors
   int color[V]; //make color matrix for each vertex
   for (int i = 0; i < V; i++)
      color[i] = 0; //initially set to 0
   if (mColoring(colors, color, 0) == false) { //for vertex 0 check graph coloring
      cout << "Solution does not exist.";
   }
   cout << "Assigned Colors are: n";
   for (int i = 0; i < V; i++)
      cout << color[i] << " ";
   return 0;
}

Output


Assigned Colors are: 
1 2 3 1 


public class mcolouring {
   static int V = 4;
   static int graph[][] = {
      {0, 1, 1, 0},
      {1, 0, 1, 1},
      {1, 1, 0, 1},
      {0, 1, 1, 0},
   };
   static boolean isValid(int v,int color[], int c) { //check whether putting a color valid for v
      for (int i = 0; i < V; i++)
         if (graph[v][i] != 0 && c == color[i])
            return false;
      return true;
   }
   static boolean mColoring(int colors, int color[], int vertex) {
      if (vertex == V) //when all vertices are considered
         return true;
      for (int col = 1; col <= colors; col++) {
         if (isValid(vertex,color, col)) { //check whether color col is valid or not
            color[vertex] = col;
            if (mColoring (colors, color, vertex+1) == true) //go for additional vertices
               return true;
            color[vertex] = 0;
         }
      }
      return false; //when no colors can be assigned
   }
   public static void main(String args[]) {
      int colors = 3; // Number of colors
      int color[] = new int[V]; //make color matrix for each vertex
      for (int i = 0; i < V; i++)
         color[i] = 0; //initially set to 0
      if (mColoring(colors, color, 0) == false) { //for vertex 0 check graph coloring
         System.out.println("Solution does not exist.");
      }
      System.out.println("Assigned Colors are: ");
      for (int i = 0; i < V; i++)
         System.out.print(color[i] + " ");
   }
}

Output


Assigned Colors are:
1 2 3 1


V = 4
graph = [[0, 1, 1, 0], [1, 0, 1, 1], [1, 1, 0, 1], [0, 1, 1, 0]]
def isValid(v, color, c):  # check whether putting a color valid for v
    for i in range(V):
        if graph[v][i] and c == color[i]:
            return False
    return True
def mColoring(colors, color, vertex):
    if vertex == V:  # when all vertices are considered
        return True
    for col in range(1, colors + 1):
        if isValid(vertex, color,
                   col):  # check whether color col is valid or not
            color[vertex] = col
            if mColoring(colors, color, vertex + 1):
                return True  # go for additional vertices
            color[vertex] = 0
    return False  # when no colors can be assigned
colors = 3  # Number of colors
color = [0] * V  # make color matrix for each vertex
if not mColoring(
        colors, color,
        0):  # initially set to 0 and for Vertex 0 check graph coloring
    print("Solution does not exist.")
else:
    print("Assigned Colors are:")
    for i in range(V):
        print(color[i], end=" ")

Output


Assigned Colors are:
1 2 3 1 

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