A single-phase AC voltage converter has the following details −

ON time = 6 min, OFF time = 4 min, frequency = 50Hz, and

Voltage source V_o = 110V

Calculate the following.

Triggering angle α

Solution −

$T=2times left ( T_{ON}+T_{OFF} right )$ but $f=50Hz,$ $T=2times left ( 6+4 right )=20mins$

$360^{circ}=20min,$ $1min=18^{circ}$

Therefore, $T_{OFF}=4min$

Then,

$$alpha =frac{4}{0.1}times 1.8=72^{circ}$$

Voltage Output

Solution −

$$V_{0}=left ( V_{S}times D right ),quad where quad D=frac{T_{ON}}{T_{ON}+T_{OFF}}=frac{6}{10}=0.6$$
$$T_{ON}=6min,quad T_{OFF}=4 min,quad V_{S}=110V$$
$$V_{0}left ( Voltage Output right )=V_{S}times D=110times 0.6=66Volts$$