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PHP uses mysqli query() or mysql_query() function to select records in a MySQL table using Like clause. This function takes two parameters and returns TRUE on success or FALSE on failure.
Syntax
$mysqli->query($sql,$resultmode)
| Sr.No. | Parameter & Description |
|---|---|
| 1 |
$sql
Required – SQL query to select records in a MySQL table using Like Clause. |
| 2 |
$resultmode
Optional – Either the constant MYSQLI_USE_RESULT or MYSQLI_STORE_RESULT depending on the desired behavior. By default, MYSQLI_STORE_RESULT is used. |
Example
Try the following example to select a record using like clause in a table −
Copy and paste the following example as mysql_example.php −
<html>
<head>
<title>Using Like Clause</title>
</head>
<body>
<?php
$dbhost = ''localhost'';
$dbuser = ''root'';
$dbpass = ''root@123'';
$dbname = ''TUTORIALS'';
$mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if($mysqli->connect_errno ) {
printf("Connect failed: %s<br />", $mysqli->connect_error);
exit();
}
printf(''Connected successfully.<br />'');
$sql = ''SELECT tutorial_id, tutorial_title, tutorial_author, submission_date FROM tutorials_tbl where tutorial_author like "Mah%"'';
$result = $mysqli->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
printf("Id: %s, Title: %s, Author: %s, Date: %d <br />",
$row["tutorial_id"],
$row["tutorial_title"],
$row["tutorial_author"],
$row["submission_date"]);
}
} else {
printf(''No record found.<br />'');
}
mysqli_free_result($result);
$mysqli->close();
?>
</body>
</html>
Output
Access the mysql_example.php deployed on apache web server and verify the output. Here we”ve entered multiple records in the table before running the select script.
Connected successfully. Id: 1, Title: MySQL Tutorial, Author: Mahesh, Date: 2021 Id: 2, Title: HTML Tutorial, Author: Mahesh, Date: 2021 Id: 3, Title: PHP Tutorial, Author: Mahesh, Date: 2021
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