Category: springbootcli

Spring Boot CLI – Packaging Application ”; Previous Next Spring boot CLI provides jar command in order to package a application as jar file. Let”s test the sample project created in Starter Thymeleaf Project Chapter to demonstrate the packaging capabilities of Spring CLI. Follow the below mentioned step to package the sample project. Package the application Type the following command E:/Test/TestApplication/> spring jar TestApplication.jar *.groovy Output Now you can see two new files created in TestApplication folder. TestApplication.jar − An executable jar file. TestApplication.jar.original − Original jar file. Include/Exclude By default following directories are included along with their contents. public resources static templates META-INF By default following directories are excluded along with their contents. repository build target *.jar files *.groovy files Using –include, we can include directories excluded otherwise. Using –exclude, we can exclude directories included otherwise. Running the Executable Jar Type the following command E:/Test/TestApplication/> java -jar TestApplication.jar You can see the following output on console. . ____ _ __ _ _ /\ / ___”_ __ _ _(_)_ __ __ _ ( ( )___ | ”_ | ”_| | ”_ / _` | \/ ___)| |_)| | | | | || (_| | ) ) ) ) ” |____| .__|_| |_|_| |___, | / / / / =========|_|==============|___/=/_/_/_/ :: Spring Boot :: (v2.6.3) 2022-02-03 11:47:42.298 INFO 8908 — [ main] .b.c.a.PackagedSpringApplicationLauncher : Starting PackagedSpringApplicationLauncher using Java 11.0.11 on DESKTOP-86KD9FC with PID 8908 (E:TestTestApplicationTestApplication.jar started by intel in E:TestTestApplication) 2022-02-03 11:47:42.310 INFO 8908 — [ main] .b.c.a.PackagedSpringApplicationLauncher : No active profile set, falling back to default profiles: default 2022-02-03 11:47:44.839 INFO 8908 — [ main] o.s.b.w.embedded.tomcat.TomcatWebServer : Tomcat initialized with port(s): 8080 (http) 2022-02-03 11:47:44.863 INFO 8908 — [ main] o.apache.catalina.core.StandardService : Starting service [Tomcat] 2022-02-03 11:47:44.864 INFO 8908 — [ main] org.apache.catalina.core.StandardEngine : Starting Servlet engine: [Apache Tomcat/9.0.56] 2022-02-03 11:47:44.958 INFO 8908 — [ main] o.a.c.c.C.[Tomcat].[localhost].[/] : Initializing Spring embedded WebApplicationContext 2022-02-03 11:47:44.959 INFO 8908 — [ main] w.s.c.ServletWebServerApplicationContext : Root WebApplicationContext: initialization completed in 1943 ms 2022-02-03 11:47:45.592 INFO 8908 — [ main] o.s.b.a.w.s.WelcomePageHandlerMapping : Adding welcome page: class path resource [static/index.html] 2022-02-03 11:47:46.492 INFO 8908 — [ main] o.s.b.w.embedded.tomcat.TomcatWebServer : Tomcat started on port(s): 8080 (http) with context path ”” 2022-02-03 11:47:46.514 INFO 8908 — [ main] .b.c.a.PackagedSpringApplicationLauncher : Started PackagedSpringApplicationLauncher in 5.295 seconds (JVM running for 6.089) Browse the application in Browser Our spring based rest application is now ready. Open url as “http://localhost:8080/” and you will see the following output. Go to Message Click on Message link and you will see the following output. Message: Welcome to TutorialsPoint.Com! Print Page Previous Next Advertisements ”;

Spring Boot CLI – Creating Project ”; Previous Next Spring Boot CLI can be used to create a new project with maven as default build tool using init command. Maven will use https://start.spring.io service. In the following example, we will create a web application using thymeleaf. Go to E:Test folder and type the following command − E:/Test> spring init –dependencies = web,thymeleaf MavenApplication.zip The above command will generate the following output − Using service at https://start.spring.io Content saved to MavenApplication.zip Create Gradle project We can create a Gradle based project as well by setting –build as gradle. To understand this in a better way, consider the example given below. Go to E:Test folder and type the following command − E:/Test> spring init –build = gradle –java-version = 1.8 –dependencies = web,thymeleaf –packaging = war GradleApplication.zip The above command will generate the following output − Using service at https://start.spring.io Content saved to GradleApplication.zip Print Page Previous Next Advertisements ”;