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Java – Files mismatch() Method ”; Previous Next Files mismatch() Method The mismatch() method is available in Files class from Java 12 onwards. It provides an easy way to compare two files. Syntax The syntax of the Files.mismatch() method is – public static long mismatch(Path path, Path path2) throws IOException Where If there is no mismatch then 1L is returned else position of first mismatch is returned. Mismatch is accounted in case if file sizes are not matching or byte contents are not matching. A file is considered identical in following cases. If both locations are pointing to same file. In case path is same and file is not present, files are considered same. If files are of same size and each byte is first files matches with corresponding bytes of second file. Parameters path − the path to the first file path2 − the path to the second file Return Value The position of the first mismatch or -1L if no mismatch. Exceptions IOException − If an I/O error occurs. SecurityException − In the case of the default provider, and a security manager is installed, the checkRead() method is invoked to check read access to both files. Files mismatch() Method Examples Example: No Mismatch in Files In this example, we”ve created two txt files in temporary directory and then written same content to both the files. Using Files.mismatch() method, both files are compared to be identical or not. Based on result returned, we”re printing the message. As both file contents are same, a message will be printed as “Files matched”. import java.io.IOException; import java.nio.file.Files; import java.nio.file.Path; public class APITester { public static void main(String[] args) throws IOException { // create two files in temp directory Path path1 = Files.createTempFile(“file1”, “.txt”); Path path2 = Files.createTempFile(“file2”, “.txt”); // write same content to both the files Files.writeString(path1, “tutorialspoint”); Files.writeString(path2, “tutorialspoint”); // check files for Mismatch, // being same content, it should return -1. long mismatch = Files.mismatch(path1, path2); // print the message based on mismatch result if(mismatch > 1L) { System.out.println(“Mismatch occurred in file1 and file2 at : ” + mismatch); }else { System.out.println(“Files matched”); } // delete the files path1.toFile().deleteOnExit(); path2.toFile().deleteOnExit(); } } Output Let us compile and run the above program, this will produce the following result − Files matched Example: Mismatch Identification in Files In this example, we”ve created two txt files in temporary directory and then written different content to the files. Using Files.mismatch() method, both files are compared to be identical or not. Based on result returned, we”re printing the message. As both file contents are different, mismatch method returns the position of first mismatch which will be printed as the output. import java.io.IOException; import java.nio.file.Files; import java.nio.file.Path; public class APITester { public static void main(String[] args) throws IOException { // create two files in temp directory Path path1 = Files.createTempFile(“file1”, “.txt”); Path path2 = Files.createTempFile(“file2”, “.txt”); // write same content to both the files Files.writeString(path1, “tutorialspoint”); Files.writeString(path2, “tutorialspoint Java 12”); // check files for Mismatch, // being different content, it should return index of first mismatch. long mismatch = Files.mismatch(path1, path2); // print the message based on mismatch result if(mismatch > 1L) { System.out.println(“Mismatch occurred in file1 and file2 at : ” + mismatch); }else { System.out.println(“Files matched”); } // delete the files path1.toFile().deleteOnExit(); path2.toFile().deleteOnExit(); } } Output Let us compile and run the above program, this will produce the following result − Mismatch occurred in file1 and file3 at : 14 Print Page Previous Next Advertisements ”;