PHP & MySQL – Like Clause

PHP & MySQL – Like Clause Example ”; Previous Next PHP uses mysqli query() or mysql_query() function to select records in a MySQL table using Like clause. This function takes two parameters and returns TRUE on success or FALSE on failure. Syntax $mysqli->query($sql,$resultmode) Sr.No. Parameter & Description 1 $sql Required – SQL query to select records in a MySQL table using Like Clause. 2 $resultmode Optional – Either the constant MYSQLI_USE_RESULT or MYSQLI_STORE_RESULT depending on the desired behavior. By default, MYSQLI_STORE_RESULT is used. Example Try the following example to select a record using like clause in a table − Copy and paste the following example as mysql_example.php − <html> <head> <title>Using Like Clause</title> </head> <body> <?php $dbhost = ”localhost”; $dbuser = ”root”; $dbpass = ”root@123”; $dbname = ”TUTORIALS”; $mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname); if($mysqli->connect_errno ) { printf(“Connect failed: %s<br />”, $mysqli->connect_error); exit(); } printf(”Connected successfully.<br />”); $sql = ”SELECT tutorial_id, tutorial_title, tutorial_author, submission_date FROM tutorials_tbl where tutorial_author like “Mah%””; $result = $mysqli->query($sql); if ($result->num_rows > 0) { while($row = $result->fetch_assoc()) { printf(“Id: %s, Title: %s, Author: %s, Date: %d <br />”, $row[“tutorial_id”], $row[“tutorial_title”], $row[“tutorial_author”], $row[“submission_date”]); } } else { printf(”No record found.<br />”); } mysqli_free_result($result); $mysqli->close(); ?> </body> </html> Output Access the mysql_example.php deployed on apache web server and verify the output. Here we”ve entered multiple records in the table before running the select script. Connected successfully. Id: 1, Title: MySQL Tutorial, Author: Mahesh, Date: 2021 Id: 2, Title: HTML Tutorial, Author: Mahesh, Date: 2021 Id: 3, Title: PHP Tutorial, Author: Mahesh, Date: 2021 Print Page Previous Next Advertisements ”;

PHP & MySQL – Create Tables

PHP & MySQL – Create Table ”; Previous Next PHP uses mysqli query() or mysql_query() function to create a MySQL table. This function takes two parameters and returns TRUE on success or FALSE on failure. Syntax $mysqli->query($sql,$resultmode) Sr.No. Parameter & Description 1 $sql Required – SQL query to create a MySQL table. 2 $resultmode Optional – Either the constant MYSQLI_USE_RESULT or MYSQLI_STORE_RESULT depending on the desired behavior. By default, MYSQLI_STORE_RESULT is used. Example Try the following example to create a table − Copy and paste the following example as mysql_example.php − <html> <head> <title>Creating MySQL Table</title> </head> <body> <?php $dbhost = ”localhost”; $dbuser = ”root”; $dbpass = ”root@123”; $dbname = ”TUTORIALS”; $mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname); if($mysqli->connect_errno ) { printf(“Connect failed: %s<br />”, $mysqli->connect_error); exit(); } printf(”Connected successfully.<br />”); $sql = “CREATE TABLE tutorials_tbl( “. “tutorial_id INT NOT NULL AUTO_INCREMENT, “. “tutorial_title VARCHAR(100) NOT NULL, “. “tutorial_author VARCHAR(40) NOT NULL, “. “submission_date DATE, “. “PRIMARY KEY ( tutorial_id )); “; if ($mysqli->query($sql)) { printf(“Table tutorials_tbl created successfully.<br />”); } if ($mysqli->errno) { printf(“Could not create table: %s<br />”, $mysqli->error); } $mysqli->close(); ?> </body> </html> Output Access the mysql_example.php deployed on apache web server and verify the output. Connected successfully. Table tutorials_tbl created successfully. Print Page Previous Next Advertisements ”;