MySQL – ORDER BY CLAUSE
Table of content
- MySQL ORDER BY Clause
- ORDER BY with DESC
- ORDER BY with Multiple Columns
- ORDER BY with ASC and DESC
- ORDER BY with LENGTH()
- Order By Clause Using a Client Program
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MySQL ORDER BY Clause
The MySQL ORDER BY clause is used to sort one or more columns of a table in provided order that can be either ascending or descending order. By default, it sorts the column(s) in ascending order if the sort order is not specified.
The sort is specified with two keywords; ASC for ascending order and DESC for descending order.
Using the ORDER BY clause, we can sort multiple columns of a table and provide different sort orders for each column. For instance, we can sort the result set first by one column, and then by another column to the first column, and so on.
Syntax
Following is the syntax of ORDER BY clause in MySQL −
SELECT column-list FROM table_name [ORDER BY column1, column2, ..., columnN] [ASC|DESC]
Here,
-
column-list are the names of the columns that we want to retrieve from the table_name.
-
column1, column2,…columnN are the column(s) that we want to order (sort).
-
ASC will sort the columns in ascending order.
-
DESC will sort the columns in descending order.
By default, the ORDER BY clause sorts the provided column in Ascending order.
Example
Firstly, let us create a table named CUSTOMERS using the following query −
CREATE TABLE CUSTOMERS ( ID INT NOT NULL, NAME VARCHAR (20) NOT NULL, AGE INT NOT NULL, ADDRESS CHAR (25), SALARY DECIMAL (18, 2), PRIMARY KEY (ID) );
The following query inserts 7 records into the above-created table −
INSERT INTO CUSTOMERS (ID,NAME,AGE,ADDRESS,SALARY) VALUES (1, ''Ramesh'', 32, ''Ahmedabad'', 2000.00 ), (2, ''Khilan'', 25, ''Delhi'', 1500.00 ), (3, ''Kaushik'', 23, ''Kota'', 2000.00 ), (4, ''Chaitali'', 25, ''Mumbai'', 6500.00 ), (5, ''Hardik'', 27, ''Bhopal'', 8500.00 ), (6, ''Komal'', 22, ''Hyderabad'', 4500.00 ), (7, ''Muffy'', 24, ''Indore'', 10000.00 );
Execute the following query to verify whether the CUSTOMERS table is created or not −
Select * from CUSTOMERS;
The CUSTOMERS table has been created successfully −
ID | NAME | AGE | ADDRESS | SALARY |
---|---|---|---|---|
1 | Ramesh | 32 | Ahmedabad | 2000.00 |
2 | Khilan | 25 | Delhi | 1500.00 |
3 | Kaushik | 23 | Kota | 2000.00 |
4 | Chaitali | 25 | Mumbai | 6500.00 |
5 | Hardik | 27 | Bhopal | 8500.00 |
6 | Komal | 22 | Hyderabad | 4500.00 |
7 | Muffy | 24 | Indore | 10000.00 |
Now, let us display all the columns from the CUSTOMERS table, sorted by the NAME column −
By default, the ORDER BY clause sorts the provided column in Ascending order.
SELECT * FROM CUSTOMERS ORDER BY NAME;
Output
As we can see in the output below, the NAME column is sorted in Ascending order.
ID | NAME | AGE | ADDRESS | SALARY |
---|---|---|---|---|
4 | Chaitali | 25 | Mumbai | 6500.00 |
5 | Hardik | 27 | Bhopal | 8500.00 |
3 | Kaushik | 23 | Kota | 2000.00 |
2 | Khilan | 25 | Delhi | 1500.00 |
6 | Komal | 22 | Hyderabad | 4500.00 |
7 | Muffy | 24 | Indore | 10000.00 |
1 | Ramesh | 32 | Ahmedabad | 2000.00 |
ORDER BY with DESC
We can sort a particular column of a table in descending order by using the ORDER BY clause along with the DESC keyword. Let us understand with the following example.
Example
In the following query, we are displaying all the columns from the CUSTOMERS table, sorted by the NAME column in descending order −
SELECT * FROM CUSTOMERS ORDER BY NAME DESC;
Output
As we can see in the output below, the NAME column is sorted in descending order.
ID | NAME | AGE | ADDRESS | SALARY |
---|---|---|---|---|
1 | Ramesh | 32 | Ahmedabad | 2000.00 |
7 | Muffy | 24 | Indore | 10000.00 |
6 | Komal | 22 | Hyderabad | 4500.00 |
2 | Khilan | 25 | Delhi | 1500.00 |
3 | Kaushik | 23 | Kota | 2000.00 |
5 | Hardik | 27 | Bhopal | 8500.00 |
4 | Chaitali | 25 | Mumbai | 6500.00 |
ORDER BY with Multiple Columns
We can also sort multiple columns of a MySQL table. To do so, we need to specify all the column names in the ORDER BY clause.
Example
Here, we are selecting all the columns from the CUSTOMERS table, sorted by the ADDRESS and NAME columns.
SELECT * FROM CUSTOMERS ORDER BY ADDRESS, NAME;
Output
The above query first sorts the ADDRESS column in ascending order, and for any rows that have the same ADDRESS value, they will be sorted by the NAME column in ascending order.
This means, all the rows with the same ADDRESS value will be grouped together and sorted by NAME.
ID | NAME | AGE | ADDRESS | SALARY |
---|---|---|---|---|
1 | Ramesh | 32 | Ahmedabad | 2000.00 |
5 | Hardik | 27 | Bhopal | 8500.00 |
2 | Khilan | 25 | Delhi | 1500.00 |
6 | Komal | 22 | Hyderabad | 4500.00 |
7 | Muffy | 24 | Indore | 10000.00 |
3 | Kaushik | 23 | Kota | 2000.00 |
4 | Chaitali | 25 | Mumbai | 6500.00 |
ORDER BY with ASC and DESC
In MySQL, we can order the columns with ASC and DESC in the same query. The column provided first with ASC will be sorted in Ascending order and the column provided second with DESC will be sorted in descending order.
Example
In this query, we are selecting all the columns from the CUSTOMERS table, sorted ascending by the AGE and descending by the SALARY column −
SELECT * FROM CUSTOMERS ORDER BY AGE ASC, SALARY DESC;
Output
On executing the given program, the output is displayed as follows −
ID | NAME | AGE | ADDRESS | SALARY |
---|---|---|---|---|
6 | Komal | 22 | Hyderabad | 4500.00 |
3 | Kaushik | 23 | Kota | 2000.00 |
7 | Muffy | 24 | Indore | 10000.00 |
4 | Chaitali | 25 | Mumbai | 6500.00 |
2 | Khilan | 25 | Delhi | 1500.00 |
5 | Hardik | 27 | Bhopal | 8500.00 |
1 | Ramesh | 32 | Ahmedabad | 2000.00 |
ORDER BY with LENGTH()
We can use the LENGTH() function with the ORDER BY clause in MySQL to sort the values present in a particular column based on the length.
Example
Using the following query, we are sorting the ADDRESS column based on the length −
SELECT * FROM CUSTOMERS ORDER BY LENGTH(ADDRESS) ASC;
Output
The output for the program above is produced as given below −
ID | NAME | AGE | ADDRESS | SALARY |
---|---|---|---|---|
3 | Kaushik | 23 | Kota | 2000.00 |
2 | Khilan | 25 | Delhi | 1500.00 |
4 | Chaitali | 25 | Mumbai | 6500.00 |
5 | Hardik | 27 | Bhopal | 8500.00 |
7 | Muffy | 24 | Indore | 10000.00 |
1 | Ramesh | 32 | Ahmedabad | 2000.00 |
6 | Komal | 22 | Hyderabad | 4500.00 |
Order By Clause Using a Client Program
Besides using MySQL ORDER BY clause to sort one or more columns of a table, we can also use client programs like Node.js, PHP, Java, and Python to achieve the same result.
Syntax
Following are the syntaxes of this operation in various programming languages −
To sort one or more columns of a MySQL table through PHP program, we need to execute SELECT statement with ORDER BY clause using the mysqli function query() as follows −
$sql = "SELECT COLUMN1, COLUMN2, .. FROM TABLE_NAME ORDER BY COLUMN1, COLUMN2, ... ASC|DESC"; $mysqli->query($sql);
To sort one or more columns of a MySQL table through Node.js program, we need to execute SELECT statement with ORDER BY clause using the query() function of the mysql2 library as follows −
sql= SELECT column-list FROM table_name [ORDER BY column1, column2, ..., columnN] [ASC|DESC] con.query(sql);
To sort one or more columns of a MySQL table through Java program, we need to execute SELECT statement with ORDER BY clause using the JDBC function executeUpdate() as follows −
String sql = "SELECT column-list FROM table_name [ORDER BY column1, column2, ..., columnN] [ASC|DESC]"; statement.executeQuery(sql);
To sort one or more columns of a MySQL table through Python program, we need to execute SELECT statement with ORDER BY clause using the execute() function of the MySQL Connector/Python as follows −
order_by_clause_query = SELECT column-list FROM table_name [ORDER BY column1, column2, ..., columnN] [ASC|DESC] cursorObj.execute(order_by_clause_query);
Example
Following are the programs −
$dbhost = ''localhost''; $dbuser = ''root''; $dbpass = ''password''; $dbname = ''TUTORIALS''; $mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname); if($mysqli->connect_errno ) { printf("Connect failed: %s
", $mysqli->connect_error); exit(); } //printf(''Connected successfully.
''); $sql = ''SELECT * from tutorials_tbl ORDER BY tutorial_author ASC''; $result = $mysqli->query($sql); if ($result->num_rows > 0) { printf("Table records based on ''tutorial_author'' in ascending order: n"); while($row = $result->fetch_assoc()) { printf("ID %d, Title: %s, Author: %s ", $row["tutorial_id"], $row["tutorial_title"], $row["tutorial_author"]); printf("n"); } } else { printf(''No record found.
''); } mysqli_free_result($result); $mysqli->close();
Output
The output obtained is as follows −
Table records based on ''tutorial_author'' in ascending order: ID 5, Title: Learn MySQL, Author: Abdul S ID 4, Title: Learn PHP, Author: John Poul ID 2, Title: PHP Tut, Author: New Author ID 1, Title: Java Tutorial, Author: new_author ID 3, Title: JAVA Tutorial, Author: Sanjay
var mysql = require(''mysql2''); var con = mysql.createConnection({ host: "localhost", user: "root", password: "Nr5a0204@123" }); //Connecting to MySQL con.connect(function (err) { if (err) throw err; console.log("Connected!"); console.log("--------------------------"); //Creating a Database sql = "create database TUTORIALS" con.query(sql); //Select database sql = "USE TUTORIALS" con.query(sql); //Creating table sql = "CREATE TABLE CUSTOMERS (ID INT NOT NULL, NAME VARCHAR(20) NOT NULL, AGE INT NOT NULL, ADDRESS CHAR(25), SALARY DECIMAL(18, 2), PRIMARY KEY(ID));" con.query(sql); //Inserting Records sql = "INSERT INTO CUSTOMERS(ID, NAME, AGE, ADDRESS, SALARY) VALUES(1,''Ramesh'', 32, ''Hyderabad'', 2000.00),(2,''Khilan'', 25, ''Delhi'', 1500.00),(3,''kaushik'', 23, ''Hyderabad'', 2000.00),(4,''Chaital'', 25, ''Mumbai'', 6500.00),(5,''Hardik'', 27, ''Vishakapatnam'', 8500.00),(6, ''Komal'',22, ''Vishakapatnam'', 4500.00),(7, ''Muffy'',24, ''Indore'', 10000.00);" con.query(sql); //Using ORDER BY Clause sql = "SELECT * FROM CUSTOMERS ORDER BY NAME;" con.query(sql, function(err, result){ if (err) throw err console.log(result) }); });
Output
The output produced is as follows −
Connected! -------------------------- [ { ID: 4, NAME: ''Chaital'', AGE: 25, ADDRESS: ''Mumbai'', SALARY: ''6500.00'' }, { ID: 5, NAME: ''Hardik'', AGE: 27, ADDRESS: ''Vishakapatnam'', SALARY: ''8500.00'' }, { ID: 3, NAME: ''kaushik'', AGE: 23, ADDRESS: ''Hyderabad'', SALARY: ''2000.00'' }, { ID: 2, NAME: ''Khilan'', AGE: 25, ADDRESS: ''Delhi'', SALARY: ''1500.00'' }, { ID: 6, NAME: ''Komal'', AGE: 22, ADDRESS: ''Vishakapatnam'', SALARY: ''4500.00'' }, { ID: 7, NAME: ''Muffy'', AGE: 24, ADDRESS: ''Indore'', SALARY: ''10000.00'' }, { ID: 1, NAME: ''Ramesh'', AGE: 32, ADDRESS: ''Hyderabad'', SALARY: ''2000.00'' } ]
import java.sql.Connection; import java.sql.DriverManager; import java.sql.ResultSet; import java.sql.Statement; public class OrderByClause { public static void main(String[] args) { String url = "jdbc:mysql://localhost:3306/TUTORIALS"; String user = "root"; String password = "password"; ResultSet rs; try { Class.forName("com.mysql.cj.jdbc.Driver"); Connection con = DriverManager.getConnection(url, user, password); Statement st = con.createStatement(); //System.out.println("Database connected successfully...!"); String sql = "SELECT * FROM CUSTOMERS ORDER BY NAME DESC"; rs = st.executeQuery(sql); System.out.println("Table records(in DESC order): "); while(rs.next()){ String id = rs.getString("Id"); String name = rs.getString("Name"); String age = rs.getString("Age"); String address = rs.getString("Address"); String salary = rs.getString("Salary"); System.out.println("Id: " + id +", Name: " + name + ", Age: " + age + ", Address: " + address + ", Salary: " + salary); } }catch(Exception e) { e.printStackTrace(); } } }
Output
The output obtained is as shown below −
Table records(in DESC order): Id: 1, Name: Ramesh, Age: 32, Address: Ahmedabad, Salary: 2000.00 Id: 7, Name: Muffy, Age: 24, Address: Indore, Salary: 10000.00 Id: 6, Name: Komal, Age: 22, Address: MP, Salary: 4500.00 Id: 2, Name: Khilan, Age: 25, Address: Delhi, Salary: 1500.00 Id: 3, Name: kaushik, Age: 23, Address: Kota, Salary: 2000.00 Id: 5, Name: Hardik, Age: 27, Address: Bhopal, Salary: 8500.00 Id: 4, Name: Chaitali, Age: 25, Address: Mumbai, Salary: 6500.00
import mysql.connector #establishing the connection connection = mysql.connector.connect( host=''localhost'', user=''root'', password=''password'', database=''tut'' ) # Creating a cursor object cursorObj = connection.cursor() order_by_clause_query = """ SELECT * FROM customers ORDER BY AGE ASC """ cursorObj.execute(order_by_clause_query) # Fetch all the ordered rows ordered_rows = cursorObj.fetchall() # Printing the ordered rows for row in ordered_rows: print(row) cursorObj.close() connection.close()
Output
Following is the output of the above code −
(3, ''kaushik'', 23, ''Hyderabad'', Decimal(''11000.00'')) (7, ''Muffy'', 24, ''Delhi'', Decimal(''10000.00'')) (2, ''Khilan'', 25, ''Kerala'', Decimal(''8000.00'')) (4, ''Chaital'', 25, ''Mumbai'', Decimal(''1200.00'')) (5, ''Hardik'', 27, ''Vishakapatnam'', Decimal(''10000.00'')) (6, ''Komal'', 29, ''Vishakapatnam'', Decimal(''7000.00'')) (1, ''Ramesh'', 32, ''Hyderabad'', Decimal(''4000.00''))
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