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Any groupby operation involves one of the following operations on the original object. They are −
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Splitting the Object
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Applying a function
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Combining the results
In many situations, we split the data into sets and we apply some functionality on each subset. In the apply functionality, we can perform the following operations −
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Aggregation − computing a summary statistic
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Transformation − perform some group-specific operation
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Filtration − discarding the data with some condition
Let us now create a DataFrame object and perform all the operations on it −
#import the pandas library import pandas as pd ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) print df
Its output is as follows −
Points Rank Team Year 0 876 1 Riders 2014 1 789 2 Riders 2015 2 863 2 Devils 2014 3 673 3 Devils 2015 4 741 3 Kings 2014 5 812 4 kings 2015 6 756 1 Kings 2016 7 788 1 Kings 2017 8 694 2 Riders 2016 9 701 4 Royals 2014 10 804 1 Royals 2015 11 690 2 Riders 2017
Split Data into Groups
Pandas object can be split into any of their objects. There are multiple ways to split an
object like −
- obj.groupby(”key”)
- obj.groupby([”key1”,”key2”])
- obj.groupby(key,axis=1)
Let us now see how the grouping objects can be applied to the DataFrame object
Example
# import the pandas library import pandas as pd ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) print df.groupby(''Team'')
Its output is as follows −
<pandas.core.groupby.DataFrameGroupBy object at 0x7fa46a977e50>
View Groups
# import the pandas library import pandas as pd ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) print df.groupby(''Team'').groups
Its output is as follows −
{''Kings'': Int64Index([4, 6, 7], dtype=''int64''), ''Devils'': Int64Index([2, 3], dtype=''int64''), ''Riders'': Int64Index([0, 1, 8, 11], dtype=''int64''), ''Royals'': Int64Index([9, 10], dtype=''int64''), ''kings'' : Int64Index([5], dtype=''int64'')}
Example
Group by with multiple columns −
# import the pandas library import pandas as pd ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) print df.groupby([''Team'',''Year'']).groups
Its output is as follows −
{(''Kings'', 2014): Int64Index([4], dtype=''int64''), (''Royals'', 2014): Int64Index([9], dtype=''int64''), (''Riders'', 2014): Int64Index([0], dtype=''int64''), (''Riders'', 2015): Int64Index([1], dtype=''int64''), (''Kings'', 2016): Int64Index([6], dtype=''int64''), (''Riders'', 2016): Int64Index([8], dtype=''int64''), (''Riders'', 2017): Int64Index([11], dtype=''int64''), (''Devils'', 2014): Int64Index([2], dtype=''int64''), (''Devils'', 2015): Int64Index([3], dtype=''int64''), (''kings'', 2015): Int64Index([5], dtype=''int64''), (''Royals'', 2015): Int64Index([10], dtype=''int64''), (''Kings'', 2017): Int64Index([7], dtype=''int64'')}
Iterating through Groups
With the groupby object in hand, we can iterate through the object similar to itertools.obj.
# import the pandas library import pandas as pd ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) grouped = df.groupby(''Year'') for name,group in grouped: print name print group
Its output is as follows −
2014 Points Rank Team Year 0 876 1 Riders 2014 2 863 2 Devils 2014 4 741 3 Kings 2014 9 701 4 Royals 2014 2015 Points Rank Team Year 1 789 2 Riders 2015 3 673 3 Devils 2015 5 812 4 kings 2015 10 804 1 Royals 2015 2016 Points Rank Team Year 6 756 1 Kings 2016 8 694 2 Riders 2016 2017 Points Rank Team Year 7 788 1 Kings 2017 11 690 2 Riders 2017
By default, the groupby object has the same label name as the group name.
Select a Group
Using the get_group() method, we can select a single group.
# import the pandas library import pandas as pd ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) grouped = df.groupby(''Year'') print grouped.get_group(2014)
Its output is as follows −
Points Rank Team Year 0 876 1 Riders 2014 2 863 2 Devils 2014 4 741 3 Kings 2014 9 701 4 Royals 2014
Aggregations
An aggregated function returns a single aggregated value for each group. Once the group by object is created, several aggregation operations can be performed on the grouped data.
An obvious one is aggregation via the aggregate or equivalent agg method −
# import the pandas library import pandas as pd import numpy as np ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) grouped = df.groupby(''Year'') print grouped[''Points''].agg(np.mean)
Its output is as follows −
Year 2014 795.25 2015 769.50 2016 725.00 2017 739.00 Name: Points, dtype: float64
Another way to see the size of each group is by applying the size() function −
import pandas as pd import numpy as np ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) Attribute Access in Python Pandas grouped = df.groupby(''Team'') print grouped.agg(np.size)
Its output is as follows −
Points Rank Year Team Devils 2 2 2 Kings 3 3 3 Riders 4 4 4 Royals 2 2 2 kings 1 1 1
Applying Multiple Aggregation Functions at Once
With grouped Series, you can also pass a list or dict of functions to do aggregation with, and generate DataFrame as output −
# import the pandas library import pandas as pd import numpy as np ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) grouped = df.groupby(''Team'') print grouped[''Points''].agg([np.sum, np.mean, np.std])
Its output is as follows −
Team sum mean std Devils 1536 768.000000 134.350288 Kings 2285 761.666667 24.006943 Riders 3049 762.250000 88.567771 Royals 1505 752.500000 72.831998 kings 812 812.000000 NaN
Transformations
Transformation on a group or a column returns an object that is indexed the same size of that is being grouped. Thus, the transform should return a result that is the same size as that of a group chunk.
# import the pandas library import pandas as pd import numpy as np ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) grouped = df.groupby(''Team'') score = lambda x: (x - x.mean()) / x.std()*10 print grouped.transform(score)
Its output is as follows −
Points Rank Year 0 12.843272 -15.000000 -11.618950 1 3.020286 5.000000 -3.872983 2 7.071068 -7.071068 -7.071068 3 -7.071068 7.071068 7.071068 4 -8.608621 11.547005 -10.910895 5 NaN NaN NaN 6 -2.360428 -5.773503 2.182179 7 10.969049 -5.773503 8.728716 8 -7.705963 5.000000 3.872983 9 -7.071068 7.071068 -7.071068 10 7.071068 -7.071068 7.071068 11 -8.157595 5.000000 11.618950
Filtration
Filtration filters the data on a defined criteria and returns the subset of data. The filter() function is used to filter the data.
import pandas as pd import numpy as np ipl_data = {''Team'': [''Riders'', ''Riders'', ''Devils'', ''Devils'', ''Kings'', ''kings'', ''Kings'', ''Kings'', ''Riders'', ''Royals'', ''Royals'', ''Riders''], ''Rank'': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2], ''Year'': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017], ''Points'':[876,789,863,673,741,812,756,788,694,701,804,690]} df = pd.DataFrame(ipl_data) print df.groupby(''Team'').filter(lambda x: len(x) >= 3)
Its output is as follows −
Points Rank Team Year 0 876 1 Riders 2014 1 789 2 Riders 2015 4 741 3 Kings 2014 6 756 1 Kings 2016 7 788 1 Kings 2017 8 694 2 Riders 2016 11 690 2 Riders 2017
In the above filter condition, we are asking to return the teams which have participated three or more times in IPL.
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