In this chapter, we will discuss regarding the Hubble Parameter as well as the Scale Factor.
-
Prerequisite − Cosmological Redshift, Cosmological Principles.
-
Assumption − The universe is homogenous and isotropic.
Hubble’s Constant with Fractional Rate of Change of Scale Factor
In this section, we will relate the Hubble’s Constant with fractional rate of Change of Scale Factor.
We can write velocity in the following manner and simplify.
$$v = frac{mathrm{d} r_p}{mathrm{d} t}$$
$$= frac{d[a(t)r_c}{dt}$$
$$v = frac{mathrm{d} a}{mathrm{d} t} ast frac{1}{a} ast (ar_c)$$
$$v = frac{mathrm{d} a}{mathrm{d} t} ast frac{1}{a} ast r_p$$
Here, v is the recessional velocity, a is the scale factor and rp is the proper distance between the galaxies.
Hubble’s Empirical Formula was of the nature −
$$v = H ast r_p$$
Thus, comparing the above two equations we obtain −
Hubble’s Parameter = Fractional rate of change of the scale factor
$$H = da/dt ast 1/a$$
Note − This is not a constant since the scale factor is a function of time. Hence it is called the Hubble’s parameter and not the Hubble’s constant.
Empirically we write −
$$H = V/D$$
Thus, from this equation, we can infer that since D is increasing and V is a constant, then H reduces with the time and expansion of the universe.
Friedmann Equation in Conjunction with the Robertson-Walker Model
In this section, we will understand how the Friedmann Equation is used in conjunction with the Robertson-Walker model. To understand this, let us take the following image which has a test mass at distance rp from body of mass M as an example.
Taking into consideration the above image, we can express force as −
$$F = G ast M ast frac{m}{r^2_p}$$
Here, G is the universal gravitational constant and ρ is the matter density inside the observable universe.
Now, assuming uniform mass density within the sphere we can write −
$$M = frac{4}{3} ast pi ast r_p^3 ast rho$$
Using these back in our force equation we get −
$$F = frac{4}{3} ast pi ast G ast r_p ast rho ast m$$
Thus, we can write the potential energy and kinetic energy of the mass m as −
$$V = -frac{4}{3} ast pi ast G ast r^2_p ast m ast rho$$
$$K.E = frac{1}{2} ast m ast frac{mathrm{d} r_p^2}{mathrm{d} t}$$
Using the Virial Theorem −
$$U = K.E + V$$
$$U = frac{1}{2} ast m ast left ( frac{mathrm{d} r_p}{mathrm{d} t} right )^2 – frac{4}{3} ast pi ast G ast r_p^2 ast m ast rho$$
But here, $r_p = ar_c$. So, we get −
$$U = frac{1}{2} ast m ast left ( frac{mathrm{d} a}{mathrm{d} t} right )^2 r_c^2 – frac{4}{3} ast pi ast G ast r_p^2 ast m ast rho$$
On further simplification, we obtain the Friedmann equation,
$$left ( frac{dot{a}}{a} right )^2 = frac{8pi}{3} ast G ast rho + frac{2U}{m} ast r_c^2 ast a^2$$
Here U is a constant. We also note that the universe we live in at present is dominated by matter, while the radiation energy density is very low.
Points to Remember
-
The Hubble parameter reduces with time and expansion of the universe.
-
The universe we live in at present is dominated by matter and radiation energy density is very low.
Learning working make money